What happens when you pass a String to a function in Rust?
What happens when you pass a String to a function in Rust?
When you pass a String
to a function in Rust, the ownership of that String
is transferred to the function. This means that the original variable that held the String
will no longer be valid after the function call, and attempting to use it will result in a compile-time error. This behavior is due to Rust's ownership model, which ensures memory safety by enforcing strict rules about how data is accessed and modified.
Here is a detailed explanation of what happens:
Ownership Transfer: When a String
is passed to a function, the ownership of the String
is moved to the function parameter. The original variable that held the String
is no longer valid after the function call.
fn takes_ownership(some_string: String) {
println!("{}", some_string);
}
fn main() {
let s = String::from("hello");
takes_ownership(s);
// println!("{}", s); // This line would cause a compile-time error because `s` is no longer valid.
}
Move Semantics: The move semantics in Rust mean that the function now owns the String
and is responsible for its cleanup. When the function scope ends, the String
will be dropped, and its memory will be freed.
Compile-Time Safety: Rust's compiler enforces these rules at compile time, preventing issues like double-free errors and dangling pointers. If you try to use the original variable after it has been moved, the compiler will produce an error.
Borrowing as an Alternative: If you need to use the String
after the function call, you can pass a reference to the String
instead of moving it. This is known as borrowing.
fn borrows_string(some_string: &String) {
println!("{}", some_string);
}
fn main() {
let s = String::from("hello");
borrows_string(&s);
println!("{}", s); // This is valid because `s` was borrowed, not moved.
}
Mutable Borrowing: If the function needs to modify the String
, you can pass a mutable reference.
fn modifies_string(some_string: &mut String) {
some_string.push_str...
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